What are the solutions to the equation 2x^2-15=65 ?

The solutions to the equation 2x^2-15=65 are x=2sqrt(10),x=-2sqrt(10)

Find the zeros of 2x^2-15=65

The zeros of 2x^2-15=65 are x=2sqrt(10),x=-2sqrt(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 15 = 65

x = 210, x = - 210

Decimal Notation

x = 6.32455 \dots, x = - 6.32455 \dots

Solution steps

2 x^{2} - 15 = 65

Move

15

to the right side

2 x^{2} = 80

Divide both sides by

2

x^{2} = 40

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 40, x = - 40

40 = 210

- 40 = - 210

x = 210, x = - 210

(2 x + 1) \cdot (x + 3) - x \cdot (x - 2) = 0

x^{2} + 10 x + 12 = 2 x + 52 x + 5

22 - [3 x - (2 x - 1)] = 5 x + {6 - [2 x - 7] (x - 1)}

- 27 x + 32 x^{2} - 39 = 0

x^{2} - 6 x + 3 = 0

What are the solutions to the equation 2x^2-15=65 ?
The solutions to the equation 2x^2-15=65 are x=2sqrt(10),x=-2sqrt(10)
Find the zeros of 2x^2-15=65
The zeros of 2x^2-15=65 are x=2sqrt(10),x=-2sqrt(10)