What are the solutions to the equation 400= n/2 (n+20) ?

The solutions to the equation 400= n/2 (n+20) are n=20,n=-40

Find the zeros of 400= n/2 (n+20)

The zeros of 400= n/2 (n+20) are n=20,n=-40

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400 = \frac{n}{2} (n + 20)

n = 20, n = - 40

Solution steps

400 = \frac{n}{2} (n + 20)

Multiply both sides by

2

800 = n (n + 20)

Expand

n (n + 20) : n^{2} + 20 n

800 = n^{2} + 20 n

Switch sides

n^{2} + 20 n = 800

Move

800

to the left side

n^{2} + 20 n - 800 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot ( - 800 )}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot (- 800) = 60

n_{1, 2} = \frac{- 20 \pm 60}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 20 + 60}{2 \cdot 1}, n_{2} = \frac{- 20 - 60}{2 \cdot 1}

n = \frac{- 20 + 60}{2 \cdot 1} : 20

n = \frac{- 20 - 60}{2 \cdot 1} : - 40

The solutions to the quadratic equation are:

n = 20, n = - 40

x^{2} + 5 x - 7 = - 3 x

2 x^{2} + 4 x - 126 = 0

x, x^{2} + y^{2} - k x + 6 y - 3 = 0

2 x^{2} - 4 x - 14 = 0

2 x^{2} - (a + b + 2 ab) x + (a + b) ab = 0

What are the solutions to the equation 400= n/2 (n+20) ?
The solutions to the equation 400= n/2 (n+20) are n=20,n=-40
Find the zeros of 400= n/2 (n+20)
The zeros of 400= n/2 (n+20) are n=20,n=-40