What are the solutions to the equation z^2-4z=0 ?

The solutions to the equation z^2-4z=0 are z=4,z=0

Find the zeros of z^2-4z=0

The zeros of z^2-4z=0 are z=4,z=0

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z^{2} - 4 z = 0

z = 4, z = 0

Solution steps

z^{2} - 4 z = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 0 = 4

z_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 1}, z_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 1}

z = \frac{- ( - 4 ) + 4}{2 \cdot 1} : 4

z = \frac{- ( - 4 ) - 4}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

z = 4, z = 0

y^{2} + 12 y

y^{2} + 18 y

x^{2} - 13 x - 15 = 0

(1 - x) (- 1 - x) - 3 = 0

9 x^{2} - 18 x

What are the solutions to the equation z^2-4z=0 ?
The solutions to the equation z^2-4z=0 are z=4,z=0
Find the zeros of z^2-4z=0
The zeros of z^2-4z=0 are z=4,z=0