What are the solutions to the equation w^2+6w-11=0 ?

The solutions to the equation w^2+6w-11=0 are w=-3+2sqrt(5),w=-3-2sqrt(5)

Find the zeros of w^2+6w-11=0

The zeros of w^2+6w-11=0 are w=-3+2sqrt(5),w=-3-2sqrt(5)

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w^{2} + 6 w - 11 = 0

w = - 3 + 25, w = - 3 - 25

Decimal Notation

w = 1.47213 \dots, w = - 7.47213 \dots

Solution steps

w^{2} + 6 w - 11 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 11 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 11) = 45

w_{1, 2} = \frac{- 6 \pm 4 5}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- 6 + 4 5}{2 \cdot 1}, w_{2} = \frac{- 6 - 4 5}{2 \cdot 1}

w = \frac{- 6 + 4 5}{2 \cdot 1} : - 3 + 25

w = \frac{- 6 - 4 5}{2 \cdot 1} : - 3 - 25

The solutions to the quadratic equation are:

w = - 3 + 25, w = - 3 - 25

x^{2} - 4 x + 3 = 0

- 9 x^{2} = 0

x^{2} + x = \frac{11}{4}

5 x^{2} + 3 x + 4 = 0

2 x^{2} + 3 x + 5

What are the solutions to the equation w^2+6w-11=0 ?
The solutions to the equation w^2+6w-11=0 are w=-3+2sqrt(5),w=-3-2sqrt(5)
Find the zeros of w^2+6w-11=0
The zeros of w^2+6w-11=0 are w=-3+2sqrt(5),w=-3-2sqrt(5)