What are the solutions to the equation (x-1)^2+1=0 ?

The solutions to the equation (x-1)^2+1=0 are x=i+1,x=-i+1

Find the zeros of (x-1)^2+1=0

The zeros of (x-1)^2+1=0 are x=i+1,x=-i+1

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(x - 1)^{2} + 1 = 0

x = i + 1, x = - i + 1

Solution steps

(x - 1)^{2} + 1 = 0

Move

1

to the right side

(x - 1)^{2} = - 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = - 1 : x = i + 1

Solve

x - 1 = - - 1 : x = - i + 1

The solutions to the quadratic equation are:

x = i + 1, x = - i + 1

w^{2} - 4 w = 12

2 x^{2} + 3 x + 1

x^{2} + 6 = 55

x^{2} + 0.2 x + 1 = 0

x, x^{2} y^{3} + 4 x y + x - 6 y = 2

What are the solutions to the equation (x-1)^2+1=0 ?
The solutions to the equation (x-1)^2+1=0 are x=i+1,x=-i+1
Find the zeros of (x-1)^2+1=0
The zeros of (x-1)^2+1=0 are x=i+1,x=-i+1