What are the solutions to the equation y^2-3y-18=0 ?

The solutions to the equation y^2-3y-18=0 are y=6,y=-3

Find the zeros of y^2-3y-18=0

The zeros of y^2-3y-18=0 are y=6,y=-3

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y^{2} - 3 y - 18 = 0

y = 6, y = - 3

Solution steps

y^{2} - 3 y - 18 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 18) = 9

y_{1, 2} = \frac{- ( - 3 ) \pm 9}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 3 ) + 9}{2 \cdot 1}, y_{2} = \frac{- ( - 3 ) - 9}{2 \cdot 1}

y = \frac{- ( - 3 ) + 9}{2 \cdot 1} : 6

y = \frac{- ( - 3 ) - 9}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

y = 6, y = - 3

1 3^{2} - 5^{2} = x^{2}

2 x^{2} + 4 x + 7

2 x^{2} + 4 x + 5

x^{2} + 12 x - 35 = 0

5^{2} + x^{2} = 1 5^{2}

What are the solutions to the equation y^2-3y-18=0 ?
The solutions to the equation y^2-3y-18=0 are y=6,y=-3
Find the zeros of y^2-3y-18=0
The zeros of y^2-3y-18=0 are y=6,y=-3