What are the solutions to the equation z^2+16=10z ?

The solutions to the equation z^2+16=10z are z=8,z=2

Find the zeros of z^2+16=10z

The zeros of z^2+16=10z are z=8,z=2

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z^{2} + 16 = 10 z

z = 8, z = 2

Solution steps

z^{2} + 16 = 10 z

Move

10 z

to the left side

z^{2} + 16 - 10 z = 0

Write in the standard form

a x^{2} + b x + c = 0

z^{2} - 10 z + 16 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 16 = 6

z_{1, 2} = \frac{- ( - 10 ) \pm 6}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 10 ) + 6}{2 \cdot 1}, z_{2} = \frac{- ( - 10 ) - 6}{2 \cdot 1}

z = \frac{- ( - 10 ) + 6}{2 \cdot 1} : 8

z = \frac{- ( - 10 ) - 6}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

z = 8, z = 2

7 x^{2} - 28 x + 1 = 0

x^{2} + 14 x - 15 = 0

X^{2} + 9 = 0

x^{2} - \frac{4}{3} x + \frac{4}{9} = 0

4 x^{2} = - 2

What are the solutions to the equation z^2+16=10z ?
The solutions to the equation z^2+16=10z are z=8,z=2
Find the zeros of z^2+16=10z
The zeros of z^2+16=10z are z=8,z=2