What are the solutions to the equation 5m^2+3m=7 ?

The solutions to the equation 5m^2+3m=7 are m=(-3+sqrt(149))/(10),m=(-3-sqrt(149))/(10)

Find the zeros of 5m^2+3m=7

The zeros of 5m^2+3m=7 are m=(-3+sqrt(149))/(10),m=(-3-sqrt(149))/(10)

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5 m^{2} + 3 m = 7

m = \frac{- 3 + 149}{10}, m = \frac{- 3 - 149}{10}

Decimal Notation

m = 0.92065 \dots, m = - 1.52065 \dots

Solution steps

5 m^{2} + 3 m = 7

Move

7

to the left side

5 m^{2} + 3 m - 7 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 5 ( - 7 )}{2 \cdot 5}

3^{2} - 4 \cdot 5 (- 7) = 149

m_{1, 2} = \frac{- 3 \pm 149}{2 \cdot 5}

Separate the solutions

m_{1} = \frac{- 3 + 149}{2 \cdot 5}, m_{2} = \frac{- 3 - 149}{2 \cdot 5}

m = \frac{- 3 + 149}{2 \cdot 5} : \frac{- 3 + 149}{10}

m = \frac{- 3 - 149}{2 \cdot 5} : \frac{- 3 - 149}{10}

The solutions to the quadratic equation are:

m = \frac{- 3 + 149}{10}, m = \frac{- 3 - 149}{10}

x^{2} + 4 x + 22 = 0

4 x^{2} - 4 x = 3

x^{2} + \frac{1}{2} x - 1 = 0

5 x^{2} - 2 x + 10 = 0

2 x^{2} + x - 351 = 0

What are the solutions to the equation 5m^2+3m=7 ?
The solutions to the equation 5m^2+3m=7 are m=(-3+sqrt(149))/(10),m=(-3-sqrt(149))/(10)
Find the zeros of 5m^2+3m=7
The zeros of 5m^2+3m=7 are m=(-3+sqrt(149))/(10),m=(-3-sqrt(149))/(10)