What are the solutions to the equation x^2+17x+72=0 ?

The solutions to the equation x^2+17x+72=0 are x=-8,x=-9

Find the zeros of x^2+17x+72=0

The zeros of x^2+17x+72=0 are x=-8,x=-9

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x^{2} + 17 x + 72 = 0

x = - 8, x = - 9

Solution steps

x^{2} + 17 x + 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 1 \cdot 72}{2 \cdot 1}

1 7^{2} - 4 \cdot 1 \cdot 72 = 1

x_{1, 2} = \frac{- 17 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 17 + 1}{2 \cdot 1}, x_{2} = \frac{- 17 - 1}{2 \cdot 1}

x = \frac{- 17 + 1}{2 \cdot 1} : - 8

x = \frac{- 17 - 1}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = - 8, x = - 9

\frac{- 5}{- 4}

\frac{k ^{2} - 22 k + 121}{k ^{2} - 121}

7 (2 x + 8) = 2 (8 x + 16)

- 9 x \geq - 90

∣ 3 s - 2 ∣ - 9 > - 5

What are the solutions to the equation x^2+17x+72=0 ?
The solutions to the equation x^2+17x+72=0 are x=-8,x=-9
Find the zeros of x^2+17x+72=0
The zeros of x^2+17x+72=0 are x=-8,x=-9