What are the solutions to the equation y^2+8y+14=0 ?

The solutions to the equation y^2+8y+14=0 are y=-4+sqrt(2),y=-4-sqrt(2)

Find the zeros of y^2+8y+14=0

The zeros of y^2+8y+14=0 are y=-4+sqrt(2),y=-4-sqrt(2)

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y^{2} + 8 y + 14 = 0

y = - 4 + 2, y = - 4 - 2

Decimal Notation

y = - 2.58578 \dots, y = - 5.41421 \dots

Solution steps

y^{2} + 8 y + 14 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 14 = 22

y_{1, 2} = \frac{- 8 \pm 2 2}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 8 + 2 2}{2 \cdot 1}, y_{2} = \frac{- 8 - 2 2}{2 \cdot 1}

y = \frac{- 8 + 2 2}{2 \cdot 1} : - 4 + 2

y = \frac{- 8 - 2 2}{2 \cdot 1} : - 4 - 2

The solutions to the quadratic equation are:

y = - 4 + 2, y = - 4 - 2

y, \frac{x ^{2}}{4} + \frac{y ^{2}}{9} = 1

(2 x + 5)^{2} = 0

x^{2} + 8 x - 2900 = 0

4 x^{2} - 24 x

- 5 x^{2} + 10 = 30

What are the solutions to the equation y^2+8y+14=0 ?
The solutions to the equation y^2+8y+14=0 are y=-4+sqrt(2),y=-4-sqrt(2)
Find the zeros of y^2+8y+14=0
The zeros of y^2+8y+14=0 are y=-4+sqrt(2),y=-4-sqrt(2)