What are the solutions to the equation solvefor x,8x^2+12xy-80y^2=0 ?

The solutions to the equation solvefor x,8x^2+12xy-80y^2=0 are x=(5y)/2 ,x=-4y

Find the zeros of solvefor x,8x^2+12xy-80y^2=0

The zeros of solvefor x,8x^2+12xy-80y^2=0 are x=(5y)/2 ,x=-4y

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solve for

x, 8 x^{2} + 12 x y - 80 y^{2} = 0

x = \frac{5 y}{2}, x = - 4 y

Solution steps

8 x^{2} + 12 x y - 80 y^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

8 x^{2} + 12 y x - 80 y^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 y \pm ( 12 y ) ^{2} - 4 \cdot 8 ( - 80 y ^{2} )}{2 \cdot 8}

Simplify

(12 y)^{2} - 4 \cdot 8 (- 80 y^{2}) : 52 y

x_{1, 2} = \frac{- 12 y \pm 52 y}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 12 y + 52 y}{2 \cdot 8}, x_{2} = \frac{- 12 y - 52 y}{2 \cdot 8}

x = \frac{- 12 y + 52 y}{2 \cdot 8} : \frac{5 y}{2}

x = \frac{- 12 y - 52 y}{2 \cdot 8} : - 4 y

The solutions to the quadratic equation are:

x = \frac{5 y}{2}, x = - 4 y

v^{2} - 13 v + 8 = - 4

2 x^{2} + 5 x - 7

x^{2} + 8 = 4 x

k^{2} + 14 k - 101 = - 6

x^{2} + 8 = 9 x

What are the solutions to the equation solvefor x,8x^2+12xy-80y^2=0 ?
The solutions to the equation solvefor x,8x^2+12xy-80y^2=0 are x=(5y)/2 ,x=-4y
Find the zeros of solvefor x,8x^2+12xy-80y^2=0
The zeros of solvefor x,8x^2+12xy-80y^2=0 are x=(5y)/2 ,x=-4y