What are the solutions to the equation 2(x-1)^2+3=6 ?

The solutions to the equation 2(x-1)^2+3=6 are x=sqrt(3/2)+1,x=-sqrt(3/2)+1

Find the zeros of 2(x-1)^2+3=6

The zeros of 2(x-1)^2+3=6 are x=sqrt(3/2)+1,x=-sqrt(3/2)+1

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2 (x - 1)^{2} + 3 = 6

x = \frac{3}{2} + 1, x = - \frac{3}{2} + 1

Decimal Notation

x = 2.22474 \dots, x = - 0.22474 \dots

Solution steps

2 (x - 1)^{2} + 3 = 6

Move

3

to the right side

2 (x - 1)^{2} = 3

Divide both sides by

2

(x - 1)^{2} = \frac{3}{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = \frac{3}{2} : x = \frac{3}{2} + 1

Solve

x - 1 = - \frac{3}{2} : x = - \frac{3}{2} + 1

The solutions to the quadratic equation are:

x = \frac{3}{2} + 1, x = - \frac{3}{2} + 1

(- 1 - x) (- 1 - x) = 0

7 m^{2} = 35

t, p = - 0.4 t^{2} + 128 t + 1200

x, 5 x^{2} y + 9 y^{2} x = - 1

x^{2} = 4 (x - 1)

What are the solutions to the equation 2(x-1)^2+3=6 ?
The solutions to the equation 2(x-1)^2+3=6 are x=sqrt(3/2)+1,x=-sqrt(3/2)+1
Find the zeros of 2(x-1)^2+3=6
The zeros of 2(x-1)^2+3=6 are x=sqrt(3/2)+1,x=-sqrt(3/2)+1