What are the solutions to the equation factor 15x^2-12=-8x ?

The solutions to the equation factor 15x^2-12=-8x are x= 2/3 ,x=-6/5

Find the zeros of factor 15x^2-12=-8x

The zeros of factor 15x^2-12=-8x are x= 2/3 ,x=-6/5

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15 x^{2} - 12 = - 8 x

x = \frac{2}{3}, x = - \frac{6}{5}

Decimal Notation

x = 0.66666 \dots, x = - 1.2

Solution steps

15 x^{2} - 12 = - 8 x

Move

8 x

to the left side

15 x^{2} - 12 + 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

15 x^{2} + 8 x - 12 = 0

Factor

15 x^{2} + 8 x - 12 : (3 x - 2) (5 x + 6)

(3 x - 2) (5 x + 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 2 = 0 or 5 x + 6 = 0

Solve

3 x - 2 = 0 : x = \frac{2}{3}

Solve

5 x + 6 = 0 : x = - \frac{6}{5}

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - \frac{6}{5}

4 (3 x - 6)^{2} + 5 = 21

- 16 x^{2} + 4502 x + 3 = 0

5 x^{2} - 100 = 0

3 x^{2} + 3 x = 90

x^{2} + 25 = 8 x

What are the solutions to the equation factor 15x^2-12=-8x ?
The solutions to the equation factor 15x^2-12=-8x are x= 2/3 ,x=-6/5
Find the zeros of factor 15x^2-12=-8x
The zeros of factor 15x^2-12=-8x are x= 2/3 ,x=-6/5