What are the solutions to the equation 5x^2+15x-48=2 ?

The solutions to the equation 5x^2+15x-48=2 are x=2,x=-5

Find the zeros of 5x^2+15x-48=2

The zeros of 5x^2+15x-48=2 are x=2,x=-5

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5 x^{2} + 15 x - 48 = 2

x = 2, x = - 5

Solution steps

5 x^{2} + 15 x - 48 = 2

Move

2

to the left side

5 x^{2} + 15 x - 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 5 ( - 50 )}{2 \cdot 5}

1 5^{2} - 4 \cdot 5 (- 50) = 35

x_{1, 2} = \frac{- 15 \pm 35}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 15 + 35}{2 \cdot 5}, x_{2} = \frac{- 15 - 35}{2 \cdot 5}

x = \frac{- 15 + 35}{2 \cdot 5} : 2

x = \frac{- 15 - 35}{2 \cdot 5} : - 5

The solutions to the quadratic equation are:

x = 2, x = - 5

5 = 3 x^{2} - 36 x + 108

y^{2} - 3 = - 2 y

(x - 1) (x + 3) = 5

3 x^{2} - 4 x + 12 = 0

m^{2} = 5

What are the solutions to the equation 5x^2+15x-48=2 ?
The solutions to the equation 5x^2+15x-48=2 are x=2,x=-5
Find the zeros of 5x^2+15x-48=2
The zeros of 5x^2+15x-48=2 are x=2,x=-5