What are the solutions to the equation m^2=m ?

The solutions to the equation m^2=m are m=1,m=0

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m^2=m

m^{2} = m

m = 1, m = 0

Solution steps

m^{2} = m

Move

m

to the left side

m^{2} - m = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot 0 = 1

m_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 1}, m_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 1}

m = \frac{- ( - 1 ) + 1}{2 \cdot 1} : 1

m = \frac{- ( - 1 ) - 1}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

m = 1, m = 0

- 6 x^{2} = - 150

S, S^{2} + \frac{I ^{2}}{4} = S I + I

y, x = 4 y - y^{2}

4 y^{2} = 25

x^{2} + x - 120 = 0

What are the solutions to the equation m^2=m ?
The solutions to the equation m^2=m are m=1,m=0
Find the zeros of m^2=m
The zeros of m^2=m are m=1,m=0