What are the solutions to the equation z^2-9z+18=0 ?

The solutions to the equation z^2-9z+18=0 are z=6,z=3

Find the zeros of z^2-9z+18=0

The zeros of z^2-9z+18=0 are z=6,z=3

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z^{2} - 9 z + 18 = 0

z = 6, z = 3

Solution steps

z^{2} - 9 z + 18 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 18 = 3

z_{1, 2} = \frac{- ( - 9 ) \pm 3}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 9 ) + 3}{2 \cdot 1}, z_{2} = \frac{- ( - 9 ) - 3}{2 \cdot 1}

z = \frac{- ( - 9 ) + 3}{2 \cdot 1} : 6

z = \frac{- ( - 9 ) - 3}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

z = 6, z = 3

\frac{4 λ ^{2} - 1}{4} = 0

r^{2} - 16 = - 7

0 = 2 x^{2} + 5 x - 7

25 - x^{2} = 22

x^{2} + 8 x + 5 = 0

What are the solutions to the equation z^2-9z+18=0 ?
The solutions to the equation z^2-9z+18=0 are z=6,z=3
Find the zeros of z^2-9z+18=0
The zeros of z^2-9z+18=0 are z=6,z=3