What are the solutions to the equation a^2-2a=2 ?

The solutions to the equation a^2-2a=2 are a=1+sqrt(3),a=1-sqrt(3)

Find the zeros of a^2-2a=2

The zeros of a^2-2a=2 are a=1+sqrt(3),a=1-sqrt(3)

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a^{2} - 2 a = 2

a = 1 + 3, a = 1 - 3

Decimal Notation

a = 2.73205 \dots, a = - 0.73205 \dots

Solution steps

a^{2} - 2 a = 2

Move

2

to the left side

a^{2} - 2 a - 2 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 2) = 23

a_{1, 2} = \frac{- ( - 2 ) \pm 2 3}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 2 ) + 2 3}{2 \cdot 1}, a_{2} = \frac{- ( - 2 ) - 2 3}{2 \cdot 1}

a = \frac{- ( - 2 ) + 2 3}{2 \cdot 1} : 1 + 3

a = \frac{- ( - 2 ) - 2 3}{2 \cdot 1} : 1 - 3

The solutions to the quadratic equation are:

a = 1 + 3, a = 1 - 3

x^{2} + 4 x - 16

x^{2} + 2 x - 40 = 0

a = \frac{a}{360} π r^{2}

18 x^{2} = 0

1.25 x^{2} - 5 x + 5 = 0

What are the solutions to the equation a^2-2a=2 ?
The solutions to the equation a^2-2a=2 are a=1+sqrt(3),a=1-sqrt(3)
Find the zeros of a^2-2a=2
The zeros of a^2-2a=2 are a=1+sqrt(3),a=1-sqrt(3)