What are the solutions to the equation 4x^2+3=x^2-7x ?

The solutions to the equation 4x^2+3=x^2-7x are x=(-7+sqrt(13))/6 ,x=(-7-sqrt(13))/6

Find the zeros of 4x^2+3=x^2-7x

The zeros of 4x^2+3=x^2-7x are x=(-7+sqrt(13))/6 ,x=(-7-sqrt(13))/6

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4 x^{2} + 3 = x^{2} - 7 x

x = \frac{- 7 + 13}{6}, x = \frac{- 7 - 13}{6}

Decimal Notation

x = - 0.56574 \dots, x = - 1.76759 \dots

Solution steps

4 x^{2} + 3 = x^{2} - 7 x

Move

7 x

to the left side

4 x^{2} + 3 + 7 x = x^{2}

Move

x^{2}

to the left side

3 x^{2} + 7 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 3 \cdot 3}{2 \cdot 3}

7^{2} - 4 \cdot 3 \cdot 3 = 13

x_{1, 2} = \frac{- 7 \pm 13}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 7 + 13}{2 \cdot 3}, x_{2} = \frac{- 7 - 13}{2 \cdot 3}

x = \frac{- 7 + 13}{2 \cdot 3} : \frac{- 7 + 13}{6}

x = \frac{- 7 - 13}{2 \cdot 3} : \frac{- 7 - 13}{6}

The solutions to the quadratic equation are:

x = \frac{- 7 + 13}{6}, x = \frac{- 7 - 13}{6}

(7 - 10 i) - (3 + 30 i)

\frac{x}{- 5} < 20

3 x^{3} + 2 x^{2} - 12 x - 8

2 x^{2} + 5 = 19

(x - i) (x + i)

What are the solutions to the equation 4x^2+3=x^2-7x ?
The solutions to the equation 4x^2+3=x^2-7x are x=(-7+sqrt(13))/6 ,x=(-7-sqrt(13))/6
Find the zeros of 4x^2+3=x^2-7x
The zeros of 4x^2+3=x^2-7x are x=(-7+sqrt(13))/6 ,x=(-7-sqrt(13))/6