What are the solutions to the equation 3n^2-8n+4=0 ?

The solutions to the equation 3n^2-8n+4=0 are n=2,n= 2/3

Find the zeros of 3n^2-8n+4=0

The zeros of 3n^2-8n+4=0 are n=2,n= 2/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 n^{2} - 8 n + 4 = 0

n = 2, n = \frac{2}{3}

Decimal Notation

n = 2, n = 0.66666 \dots

Solution steps

3 n^{2} - 8 n + 4 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 3 \cdot 4}{2 \cdot 3}

(- 8)^{2} - 4 \cdot 3 \cdot 4 = 4

n_{1, 2} = \frac{- ( - 8 ) \pm 4}{2 \cdot 3}

Separate the solutions

n_{1} = \frac{- ( - 8 ) + 4}{2 \cdot 3}, n_{2} = \frac{- ( - 8 ) - 4}{2 \cdot 3}

n = \frac{- ( - 8 ) + 4}{2 \cdot 3} : 2

n = \frac{- ( - 8 ) - 4}{2 \cdot 3} : \frac{2}{3}

The solutions to the quadratic equation are:

n = 2, n = \frac{2}{3}

- 3 x^{2} - 11 x + 4 = 0

y^{2} = 2 y - y^{2}

x, x^{2} + x + y^{2} + \frac{3}{2} y + \frac{13}{16} = 0

c (x) = x^{2} + 6 x + 128

6 u^{2} - u - 2 = 0

What are the solutions to the equation 3n^2-8n+4=0 ?
The solutions to the equation 3n^2-8n+4=0 are n=2,n= 2/3
Find the zeros of 3n^2-8n+4=0
The zeros of 3n^2-8n+4=0 are n=2,n= 2/3