What are the solutions to the equation (2-5t)^2=12 ?

The solutions to the equation (2-5t)^2=12 are t=-(2sqrt(3)-2)/5 ,t=(2sqrt(3)+2)/5

Find the zeros of (2-5t)^2=12

The zeros of (2-5t)^2=12 are t=-(2sqrt(3)-2)/5 ,t=(2sqrt(3)+2)/5

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(2 - 5 t)^{2} = 12

t = - \frac{2 3 - 2}{5}, t = \frac{2 3 + 2}{5}

Decimal Notation

t = - 0.29282 \dots, t = 1.09282 \dots

Solution steps

(2 - 5 t)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 - 5 t = 12 : t = - \frac{2 3 - 2}{5}

Solve

2 - 5 t = - 12 : t = \frac{2 3 + 2}{5}

The solutions to the quadratic equation are:

t = - \frac{2 3 - 2}{5}, t = \frac{2 3 + 2}{5}

x^{2} + 7 x + 12 = 2

4 - \frac{10 x + 1}{6} = 4 x \frac{16 x + 3}{4}

- 2 x^{2} + 9 x + 18 = 0

4 = a (2 - h)^{2} + k, - 4 = a (- 2 - h)^{2} + k, 5 = a (1 - h)^{2} + k

x^{2} + 2 x = 2 x + 1

What are the solutions to the equation (2-5t)^2=12 ?
The solutions to the equation (2-5t)^2=12 are t=-(2sqrt(3)-2)/5 ,t=(2sqrt(3)+2)/5
Find the zeros of (2-5t)^2=12
The zeros of (2-5t)^2=12 are t=-(2sqrt(3)-2)/5 ,t=(2sqrt(3)+2)/5