What are the solutions to the equation 3u^2-27u=0 ?

The solutions to the equation 3u^2-27u=0 are u=9,u=0

Find the zeros of 3u^2-27u=0

The zeros of 3u^2-27u=0 are u=9,u=0

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3 u^{2} - 27 u = 0

u = 9, u = 0

Solution steps

3 u^{2} - 27 u = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 27 ) \pm ( - 27 ) ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

(- 27)^{2} - 4 \cdot 3 \cdot 0 = 27

u_{1, 2} = \frac{- ( - 27 ) \pm 27}{2 \cdot 3}

Separate the solutions

u_{1} = \frac{- ( - 27 ) + 27}{2 \cdot 3}, u_{2} = \frac{- ( - 27 ) - 27}{2 \cdot 3}

u = \frac{- ( - 27 ) + 27}{2 \cdot 3} : 9

u = \frac{- ( - 27 ) - 27}{2 \cdot 3} : 0

The solutions to the quadratic equation are:

u = 9, u = 0

34 = 91.966 x^{2} - 180.82 x + 94.588

t, s = 2 t - t^{2}

(k - 2) x^{2} + 3 x + k = 0

5 x^{2} + 6 = 0

x, (x + y)^{2} = 0

What are the solutions to the equation 3u^2-27u=0 ?
The solutions to the equation 3u^2-27u=0 are u=9,u=0
Find the zeros of 3u^2-27u=0
The zeros of 3u^2-27u=0 are u=9,u=0