What are the solutions to the equation x^2+18x-144=0 ?

The solutions to the equation x^2+18x-144=0 are x=6,x=-24

Find the zeros of x^2+18x-144=0

The zeros of x^2+18x-144=0 are x=6,x=-24

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x^{2} + 18 x - 144 = 0

x = 6, x = - 24

Solution steps

x^{2} + 18 x - 144 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot ( - 144 )}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot (- 144) = 30

x_{1, 2} = \frac{- 18 \pm 30}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 30}{2 \cdot 1}, x_{2} = \frac{- 18 - 30}{2 \cdot 1}

x = \frac{- 18 + 30}{2 \cdot 1} : 6

x = \frac{- 18 - 30}{2 \cdot 1} : - 24

The solutions to the quadratic equation are:

x = 6, x = - 24

2 y^{2} - 8 y = 0

2 x^{2} + 9 x - 4 = 0

5 x^{2} + 2 = x

x^{2} + 8 x - 3 = 0

- x^{2} - 2 x + 26 = 0

What are the solutions to the equation x^2+18x-144=0 ?
The solutions to the equation x^2+18x-144=0 are x=6,x=-24
Find the zeros of x^2+18x-144=0
The zeros of x^2+18x-144=0 are x=6,x=-24