What are the solutions to the equation n^2+7n=0 ?

The solutions to the equation n^2+7n=0 are n=0,n=-7

Find the zeros of n^2+7n=0

The zeros of n^2+7n=0 are n=0,n=-7

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n^{2} + 7 n = 0

n = 0, n = - 7

Solution steps

n^{2} + 7 n = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 0 = 7

n_{1, 2} = \frac{- 7 \pm 7}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 7 + 7}{2 \cdot 1}, n_{2} = \frac{- 7 - 7}{2 \cdot 1}

n = \frac{- 7 + 7}{2 \cdot 1} : 0

n = \frac{- 7 - 7}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

n = 0, n = - 7

x, 3 x^{2} + 2 x y + y^{2} = 2

4 x^{2} = 6 x + 1

2 6^{2} = 2 4^{2} + x^{2}

x^{2} + 16 x + 63 = 0

9 x^{2} - 8 x - 2 = 0

What are the solutions to the equation n^2+7n=0 ?
The solutions to the equation n^2+7n=0 are n=0,n=-7
Find the zeros of n^2+7n=0
The zeros of n^2+7n=0 are n=0,n=-7