What are the solutions to the equation solvefor x,-2x^2y=y ?

The solutions to the equation solvefor x,-2x^2y=y are x= 1/(sqrt(2))i,x=-1/(sqrt(2))i;\quad y\ne 0

Find the zeros of solvefor x,-2x^2y=y

The zeros of solvefor x,-2x^2y=y are x= 1/(sqrt(2))i,x=-1/(sqrt(2))i;\quad y\ne 0

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solve for

x, - 2 x^{2} y = y

x = \frac{1}{2} i, x = - \frac{1}{2} i; y \neq = 0

Solution steps

- 2 x^{2} y = y

Divide both sides by

- 2 y; y \neq = 0

x^{2} = - \frac{1}{2}; y \neq = 0

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{2}, x = - - \frac{1}{2}; y \neq = 0

- \frac{1}{2} = \frac{1}{2} i

- - \frac{1}{2} = - \frac{1}{2} i

x = \frac{1}{2} i, x = - \frac{1}{2} i; y \neq = 0

x^{2} + 6 x - 3.25 = 0

- x^{2} + 30 + 4 x = - 2 x^{2} + 14 x + 6

6 x^{2} - 17 x - 51 = 0

r^{2} - 7 r + 6 = 0

3 p^{2} = 75

What are the solutions to the equation solvefor x,-2x^2y=y ?
The solutions to the equation solvefor x,-2x^2y=y are x= 1/(sqrt(2))i,x=-1/(sqrt(2))i;\quad y\ne 0
Find the zeros of solvefor x,-2x^2y=y
The zeros of solvefor x,-2x^2y=y are x= 1/(sqrt(2))i,x=-1/(sqrt(2))i;\quad y\ne 0