What are the solutions to the equation 3(x)^2-6x+9=0 ?

The solutions to the equation 3(x)^2-6x+9=0 are x=1+sqrt(2)i,x=1-sqrt(2)i

Find the zeros of 3(x)^2-6x+9=0

The zeros of 3(x)^2-6x+9=0 are x=1+sqrt(2)i,x=1-sqrt(2)i

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3 (x)^{2} - 6 x + 9 = 0

x = 1 + 2 i, x = 1 - 2 i

Solution steps

3 x^{2} - 6 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 \cdot 9}{2 \cdot 3}

Simplify

(- 6)^{2} - 4 \cdot 3 \cdot 9 : 62 i

x_{1, 2} = \frac{- ( - 6 ) \pm 6 2 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6 2 i}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 6 2 i}{2 \cdot 3}

x = \frac{- ( - 6 ) + 6 2 i}{2 \cdot 3} : 1 + 2 i

x = \frac{- ( - 6 ) - 6 2 i}{2 \cdot 3} : 1 - 2 i

The solutions to the quadratic equation are:

x = 1 + 2 i, x = 1 - 2 i

- x^{2} + 3 x + 10 = 0

y, x^{2} + x y + y^{2} = 7

16 x^{2} - 16 x + 3 = 0

3 y^{2} + 8 y + 5 = 0

V = \frac{1}{3} π r^{2} h, r

What are the solutions to the equation 3(x)^2-6x+9=0 ?
The solutions to the equation 3(x)^2-6x+9=0 are x=1+sqrt(2)i,x=1-sqrt(2)i
Find the zeros of 3(x)^2-6x+9=0
The zeros of 3(x)^2-6x+9=0 are x=1+sqrt(2)i,x=1-sqrt(2)i