What are the solutions to the equation 1/4 k^2-17=-7 ?

The solutions to the equation 1/4 k^2-17=-7 are k=2sqrt(10),k=-2sqrt(10)

Find the zeros of 1/4 k^2-17=-7

The zeros of 1/4 k^2-17=-7 are k=2sqrt(10),k=-2sqrt(10)

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\frac{1}{4} k^{2} - 17 = - 7

k = 210, k = - 210

Decimal Notation

k = 6.32455 \dots, k = - 6.32455 \dots

Solution steps

\frac{1}{4} k^{2} - 17 = - 7

Move

17

to the right side

\frac{1}{4} k^{2} = 10

Multiply both sides by

4

k^{2} = 40

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

k = 40, k = - 40

40 = 210

- 40 = - 210

k = 210, k = - 210

f^{2} - 46 f = 0

- 19 = - 3 - n^{2} - 3 - n^{2}

a^{2} - 3 a - 10 = 0

2 a^{2} - 14 a = 0

7 (x + 1)^{2} - 28 = 0

What are the solutions to the equation 1/4 k^2-17=-7 ?
The solutions to the equation 1/4 k^2-17=-7 are k=2sqrt(10),k=-2sqrt(10)
Find the zeros of 1/4 k^2-17=-7
The zeros of 1/4 k^2-17=-7 are k=2sqrt(10),k=-2sqrt(10)