What are the solutions to the equation 4x^2-12x+6=0 ?

The solutions to the equation 4x^2-12x+6=0 are x=(3+sqrt(3))/2 ,x=(3-sqrt(3))/2

Find the zeros of 4x^2-12x+6=0

The zeros of 4x^2-12x+6=0 are x=(3+sqrt(3))/2 ,x=(3-sqrt(3))/2

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4 x^{2} - 12 x + 6 = 0

x = \frac{3 + 3}{2}, x = \frac{3 - 3}{2}

Decimal Notation

x = 2.36602 \dots, x = 0.63397 \dots

Solution steps

4 x^{2} - 12 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 6}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 \cdot 6 = 43

x_{1, 2} = \frac{- ( - 12 ) \pm 4 3}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4 3}{2 \cdot 4}, x_{2} = \frac{- ( - 12 ) - 4 3}{2 \cdot 4}

x = \frac{- ( - 12 ) + 4 3}{2 \cdot 4} : \frac{3 + 3}{2}

x = \frac{- ( - 12 ) - 4 3}{2 \cdot 4} : \frac{3 - 3}{2}

The solutions to the quadratic equation are:

x = \frac{3 + 3}{2}, x = \frac{3 - 3}{2}

x, 5 x^{2} + 3 y^{2} + 10 x + 6 y + 14 = 0

x^{2} + 2 x - 48 = 0

(x - 3)^{2} + 4 = 0

- 6 x^{2} + 30 x - 36 = 0

x, 2 x^{2} = 0

What are the solutions to the equation 4x^2-12x+6=0 ?
The solutions to the equation 4x^2-12x+6=0 are x=(3+sqrt(3))/2 ,x=(3-sqrt(3))/2
Find the zeros of 4x^2-12x+6=0
The zeros of 4x^2-12x+6=0 are x=(3+sqrt(3))/2 ,x=(3-sqrt(3))/2