What are the solutions to the equation completesquare x^2-x-1=0 ?

The solutions to the equation completesquare x^2-x-1=0 are x=(sqrt(5)+1)/2 ,x=(-sqrt(5)+1)/2

Find the zeros of completesquare x^2-x-1=0

The zeros of completesquare x^2-x-1=0 are x=(sqrt(5)+1)/2 ,x=(-sqrt(5)+1)/2

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x^{2} - x - 1 = 0

x = \frac{5 + 1}{2}, x = \frac{- 5 + 1}{2}

Decimal Notation

x = 1.61803 \dots, x = - 0.61803 \dots

Solution steps

x^{2} - x - 1 = 0

Move

1

to the right side

x^{2} - x = 1

Rewrite in the form

(x + a)^{2} = b

(x - \frac{1}{2})^{2} = \frac{5}{4}

For

the solutions are

f (x) = a, - a

Solve

x - \frac{1}{2} = \frac{5}{4} : x = \frac{5 + 1}{2}

Solve

x - \frac{1}{2} = - \frac{5}{4} : x = \frac{- 5 + 1}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 1}{2}, x = \frac{- 5 + 1}{2}

13870 = - 245 x^{2} - 196 x + 13857

20 x^{2} - 24 x + 65

(6 x - 7)^{2} = - 25

6 x^{2} + 10 x + 3 = 0

- 3 x^{2} - 3 x + 2 = 0

What are the solutions to the equation completesquare x^2-x-1=0 ?
The solutions to the equation completesquare x^2-x-1=0 are x=(sqrt(5)+1)/2 ,x=(-sqrt(5)+1)/2
Find the zeros of completesquare x^2-x-1=0
The zeros of completesquare x^2-x-1=0 are x=(sqrt(5)+1)/2 ,x=(-sqrt(5)+1)/2