What are the solutions to the equation 5(x+1)^2=3x+299 ?

The solutions to the equation 5(x+1)^2=3x+299 are x=7,x=-42/5

Find the zeros of 5(x+1)^2=3x+299

The zeros of 5(x+1)^2=3x+299 are x=7,x=-42/5

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5 (x + 1)^{2} = 3 x + 299

x = 7, x = - \frac{42}{5}

Decimal Notation

x = 7, x = - 8.4

Solution steps

5 (x + 1)^{2} = 3 x + 299

Expand

5 (x + 1)^{2} : 5 x^{2} + 10 x + 5

5 x^{2} + 10 x + 5 = 3 x + 299

Move

299

to the left side

5 x^{2} + 10 x - 294 = 3 x

Move

3 x

to the left side

5 x^{2} + 7 x - 294 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 5 ( - 294 )}{2 \cdot 5}

7^{2} - 4 \cdot 5 (- 294) = 77

x_{1, 2} = \frac{- 7 \pm 77}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 7 + 77}{2 \cdot 5}, x_{2} = \frac{- 7 - 77}{2 \cdot 5}

x = \frac{- 7 + 77}{2 \cdot 5} : 7

x = \frac{- 7 - 77}{2 \cdot 5} : - \frac{42}{5}

The solutions to the quadratic equation are:

x = 7, x = - \frac{42}{5}

2 x^{2} - 7 x + 13 = 10

5 x^{2} + x - \frac{1}{10} = 0

7 x - 11 + 5 x^{2} = 4

- 4.9 t^{2} + 32 t = 0

5 x^{2} - 360 = - 60 x

What are the solutions to the equation 5(x+1)^2=3x+299 ?
The solutions to the equation 5(x+1)^2=3x+299 are x=7,x=-42/5
Find the zeros of 5(x+1)^2=3x+299
The zeros of 5(x+1)^2=3x+299 are x=7,x=-42/5