What are the solutions to the equation 3x^2+2x+1/3 =0 ?

The solutions to the equation 3x^2+2x+1/3 =0 are x=-1/3

Find the zeros of 3x^2+2x+1/3 =0

The zeros of 3x^2+2x+1/3 =0 are x=-1/3

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3 x^{2} + 2 x + \frac{1}{3} = 0

x = - \frac{1}{3}

Decimal Notation

x = - 0.33333 \dots

Solution steps

3 x^{2} + 2 x + \frac{1}{3} = 0

Multiply both sides by

3

9 x^{2} + 6 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 9 \cdot 1}{2 \cdot 9}

6^{2} - 4 \cdot 9 \cdot 1 = 0

x_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 9}

x = \frac{- 6}{2 \cdot 9}

\frac{- 6}{2 \cdot 9} = - \frac{1}{3}

x = - \frac{1}{3}

The solution to the quadratic equation is:

x = - \frac{1}{3}

x, f = \frac{x ^{2}}{y - 1}

x^{2} = 77 x - 70

x^{2} + 10 x = 15

x^{2} = - 9 - 6 x

- y^{2} + y + 2 = 0

What are the solutions to the equation 3x^2+2x+1/3 =0 ?
The solutions to the equation 3x^2+2x+1/3 =0 are x=-1/3
Find the zeros of 3x^2+2x+1/3 =0
The zeros of 3x^2+2x+1/3 =0 are x=-1/3