What are the solutions to the equation 2x^2-2x-40=0 ?

The solutions to the equation 2x^2-2x-40=0 are x=5,x=-4

Find the zeros of 2x^2-2x-40=0

The zeros of 2x^2-2x-40=0 are x=5,x=-4

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2 x^{2} - 2 x - 40 = 0

x = 5, x = - 4

Solution steps

2 x^{2} - 2 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 2 ( - 40 )}{2 \cdot 2}

(- 2)^{2} - 4 \cdot 2 (- 40) = 18

x_{1, 2} = \frac{- ( - 2 ) \pm 18}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 18}{2 \cdot 2}, x_{2} = \frac{- ( - 2 ) - 18}{2 \cdot 2}

x = \frac{- ( - 2 ) + 18}{2 \cdot 2} : 5

x = \frac{- ( - 2 ) - 18}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

x = 5, x = - 4

x - x^{2} = 4 x - 4 x^{2}

2 x^{2} = (\frac{6}{7}) x + 2

x, 3 x^{2} - 4 x - 4 = 0

x^{2} + 8 x = - 15

(y + 1)^{2} = 0

What are the solutions to the equation 2x^2-2x-40=0 ?
The solutions to the equation 2x^2-2x-40=0 are x=5,x=-4
Find the zeros of 2x^2-2x-40=0
The zeros of 2x^2-2x-40=0 are x=5,x=-4