What are the solutions to the equation t^2-2t=63 ?

The solutions to the equation t^2-2t=63 are t=9,t=-7

Find the zeros of t^2-2t=63

The zeros of t^2-2t=63 are t=9,t=-7

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t^{2} - 2 t = 63

t = 9, t = - 7

Solution steps

t^{2} - 2 t = 63

Move

63

to the left side

t^{2} - 2 t - 63 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 63 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 63) = 16

t_{1, 2} = \frac{- ( - 2 ) \pm 16}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 2 ) + 16}{2 \cdot 1}, t_{2} = \frac{- ( - 2 ) - 16}{2 \cdot 1}

t = \frac{- ( - 2 ) + 16}{2 \cdot 1} : 9

t = \frac{- ( - 2 ) - 16}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

t = 9, t = - 7

x, 9 x^{2} - 54 x + 9 y^{2} + 6 y + 91 = 0

0 = 2 x^{2} - 8

2 x^{2} + 11 x - 13 = 0

x^{2} + 3 x + 2 = 0

- 81 a^{2} + 90 a - 25 = 0

What are the solutions to the equation t^2-2t=63 ?
The solutions to the equation t^2-2t=63 are t=9,t=-7
Find the zeros of t^2-2t=63
The zeros of t^2-2t=63 are t=9,t=-7