What are the solutions to the equation 3n^2+21n-510=0 ?

The solutions to the equation 3n^2+21n-510=0 are n=10,n=-17

Find the zeros of 3n^2+21n-510=0

The zeros of 3n^2+21n-510=0 are n=10,n=-17

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3 n^{2} + 21 n - 510 = 0

n = 10, n = - 17

Solution steps

3 n^{2} + 21 n - 510 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 21 \pm 2 1 ^{2} - 4 \cdot 3 ( - 510 )}{2 \cdot 3}

2 1^{2} - 4 \cdot 3 (- 510) = 81

n_{1, 2} = \frac{- 21 \pm 81}{2 \cdot 3}

Separate the solutions

n_{1} = \frac{- 21 + 81}{2 \cdot 3}, n_{2} = \frac{- 21 - 81}{2 \cdot 3}

n = \frac{- 21 + 81}{2 \cdot 3} : 10

n = \frac{- 21 - 81}{2 \cdot 3} : - 17

The solutions to the quadratic equation are:

n = 10, n = - 17

432 = (2 x + 18) (2 x + 12)

2 x^{2} = - 10 x

\frac{2}{3} x^{2} + 14 = 20

6 x - 3 x^{2} = 3

2 x^{2} - x - 14 = 0

What are the solutions to the equation 3n^2+21n-510=0 ?
The solutions to the equation 3n^2+21n-510=0 are n=10,n=-17
Find the zeros of 3n^2+21n-510=0
The zeros of 3n^2+21n-510=0 are n=10,n=-17