What are the solutions to the equation (3x-2)^2=12 ?

The solutions to the equation (3x-2)^2=12 are x=(2sqrt(3)+2)/3 ,x=(-2sqrt(3)+2)/3

Find the zeros of (3x-2)^2=12

The zeros of (3x-2)^2=12 are x=(2sqrt(3)+2)/3 ,x=(-2sqrt(3)+2)/3

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(3 x - 2)^{2} = 12

x = \frac{2 3 + 2}{3}, x = \frac{- 2 3 + 2}{3}

Decimal Notation

x = 1.82136 \dots, x = - 0.48803 \dots

Solution steps

(3 x - 2)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 2 = 12 : x = \frac{2 3 + 2}{3}

Solve

3 x - 2 = - 12 : x = \frac{- 2 3 + 2}{3}

The solutions to the quadratic equation are:

x = \frac{2 3 + 2}{3}, x = \frac{- 2 3 + 2}{3}

x^{2} - 1 x - 1 = 0

(m + 1) x^{2} - 2 x + 2 (m - 1) = 0

x^{2} - 8 x - 5

x^{2} - 8 x - 2

x^{2} - 8 x + 4

What are the solutions to the equation (3x-2)^2=12 ?
The solutions to the equation (3x-2)^2=12 are x=(2sqrt(3)+2)/3 ,x=(-2sqrt(3)+2)/3
Find the zeros of (3x-2)^2=12
The zeros of (3x-2)^2=12 are x=(2sqrt(3)+2)/3 ,x=(-2sqrt(3)+2)/3