What are the solutions to the equation x(x-2)-(x+2)=8 ?

The solutions to the equation x(x-2)-(x+2)=8 are x=5,x=-2

Find the zeros of x(x-2)-(x+2)=8

The zeros of x(x-2)-(x+2)=8 are x=5,x=-2

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x (x - 2) - (x + 2) = 8

x = 5, x = - 2

Solution steps

x (x - 2) - (x + 2) = 8

Expand

x (x - 2) - (x + 2) : x^{2} - 3 x - 2

x^{2} - 3 x - 2 = 8

Move

8

to the left side

x^{2} - 3 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 10) = 7

x_{1, 2} = \frac{- ( - 3 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 7}{2 \cdot 1}

x = \frac{- ( - 3 ) + 7}{2 \cdot 1} : 5

x = \frac{- ( - 3 ) - 7}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 5, x = - 2

(2 x)^{2} + (2 x + 2)^{2} = 452

4 - x^{2} = x - 2

2 k^{2} - 4 k = 96

4 x (x + 3) + (x + 2) (x - 2) = (2 x + 3)^{2} + x - 1

6 x^{2} = 12 x

What are the solutions to the equation x(x-2)-(x+2)=8 ?
The solutions to the equation x(x-2)-(x+2)=8 are x=5,x=-2
Find the zeros of x(x-2)-(x+2)=8
The zeros of x(x-2)-(x+2)=8 are x=5,x=-2