What is 7x^{-3}*4x^{-2} ?

The solution to 7x^{-3}*4x^{-2} is (28)/(x^5)

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simplify 7x^{-3}*4x^{-2}

simplify

7 x^{- 3} \cdot 4 x^{- 2}

\frac{28}{x ^{5}}

Solution steps

7 x^{- 3} \cdot 4 x^{- 2}

Multiply the numbers:

7 \cdot 4 = 28

= 28 x^{- 3} x^{- 2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

x^{- 3} x^{- 2} = x^{- 3 - 2}

= 28 x^{- 3 - 2}

Subtract the numbers:

- 3 - 2 = - 5

= 28 x^{- 5}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

x^{- 5} = \frac{1}{x ^{5}}

= 28 \cdot \frac{1}{x ^{5}}

Simplify

28 \cdot \frac{1}{x ^{5}} : \frac{28}{x ^{5}}

= \frac{28}{x ^{5}}

- \frac{4 x}{5} < 0

(y + 10 - 3)^{2} + y^{2} = 49

\frac{4 - ( \frac{3}{4} ) ^{2}}{2 ( \frac{3}{4} )}

9512

\frac{4 n}{4 n - 4} \cdot \frac{n - 1}{n + 1}