What are the solutions to the equation (m+2)^2=5 ?

The solutions to the equation (m+2)^2=5 are m=sqrt(5)-2,m=-sqrt(5)-2

Find the zeros of (m+2)^2=5

The zeros of (m+2)^2=5 are m=sqrt(5)-2,m=-sqrt(5)-2

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(m + 2)^{2} = 5

m = 5 - 2, m = - 5 - 2

Decimal Notation

m = 0.23606 \dots, m = - 4.23606 \dots

Solution steps

(m + 2)^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

m + 2 = 5 : m = 5 - 2

Solve

m + 2 = - 5 : m = - 5 - 2

The solutions to the quadratic equation are:

m = 5 - 2, m = - 5 - 2

y^{2} - 8 y + 3 = 0

(x + 3) (2 x - 9) = 0

a^{2} + 2 = 12

(x - 2) (x + 1) = 2 - x

s^{2} + s + 4

What are the solutions to the equation (m+2)^2=5 ?
The solutions to the equation (m+2)^2=5 are m=sqrt(5)-2,m=-sqrt(5)-2
Find the zeros of (m+2)^2=5
The zeros of (m+2)^2=5 are m=sqrt(5)-2,m=-sqrt(5)-2