What are the solutions to the equation 3x^2+3x-10=0 ?

The solutions to the equation 3x^2+3x-10=0 are x=(-3+sqrt(129))/6 ,x=(-3-sqrt(129))/6

Find the zeros of 3x^2+3x-10=0

The zeros of 3x^2+3x-10=0 are x=(-3+sqrt(129))/6 ,x=(-3-sqrt(129))/6

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3 x^{2} + 3 x - 10 = 0

x = \frac{- 3 + 129}{6}, x = \frac{- 3 - 129}{6}

Decimal Notation

x = 1.39296 \dots, x = - 2.39296 \dots

Solution steps

3 x^{2} + 3 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 3 ( - 10 )}{2 \cdot 3}

3^{2} - 4 \cdot 3 (- 10) = 129

x_{1, 2} = \frac{- 3 \pm 129}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 3 + 129}{2 \cdot 3}, x_{2} = \frac{- 3 - 129}{2 \cdot 3}

x = \frac{- 3 + 129}{2 \cdot 3} : \frac{- 3 + 129}{6}

x = \frac{- 3 - 129}{2 \cdot 3} : \frac{- 3 - 129}{6}

The solutions to the quadratic equation are:

x = \frac{- 3 + 129}{6}, x = \frac{- 3 - 129}{6}

- 1 + p = - 2 p^{2}

m^{2} - 11 m - 12 = 0

- x^{2} - 12 x - 11 = - 8 x - 8

(2 x + 6) (x - 12) + x - 44 = (x + 5) (x - 4) + 5 x + 25

2.3 x 1 0^{9} = (1 x 1 0^{3}) (2.3 x 1 0^{n})

What are the solutions to the equation 3x^2+3x-10=0 ?
The solutions to the equation 3x^2+3x-10=0 are x=(-3+sqrt(129))/6 ,x=(-3-sqrt(129))/6
Find the zeros of 3x^2+3x-10=0
The zeros of 3x^2+3x-10=0 are x=(-3+sqrt(129))/6 ,x=(-3-sqrt(129))/6