What are the solutions to the equation solvefor y,9y^2=x(x-3)^2 ?

The solutions to the equation solvefor y,9y^2=x(x-3)^2 are y=(sqrt(x)(x-3))/3 ,y=-(sqrt(x)(x-3))/3

Find the zeros of solvefor y,9y^2=x(x-3)^2

The zeros of solvefor y,9y^2=x(x-3)^2 are y=(sqrt(x)(x-3))/3 ,y=-(sqrt(x)(x-3))/3

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solve for

y, 9 y^{2} = x (x - 3)^{2}

y = \frac{x ( x - 3 )}{3}, y = - \frac{x ( x - 3 )}{3}

Solution steps

9 y^{2} = x (x - 3)^{2}

Divide both sides by

9

y^{2} = \frac{x ( x - 3 ) ^{2}}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = \frac{x ( x - 3 ) ^{2}}{9}, y = - \frac{x ( x - 3 ) ^{2}}{9}

Simplify

\frac{x ( x - 3 ) ^{2}}{9} : \frac{x ( x - 3 )}{3}

Simplify

- \frac{x ( x - 3 ) ^{2}}{9} : - \frac{x ( x - 3 )}{3}

y = \frac{x ( x - 3 )}{3}, y = - \frac{x ( x - 3 )}{3}

(4 x - 1) (2 x + 2) = 12

x^{2} + 3 x + 3

x^{2} + 3 x - 4

- x^{2} + 10 x - 23 = 0

4 x^{2} + 81 = 0

What are the solutions to the equation solvefor y,9y^2=x(x-3)^2 ?
The solutions to the equation solvefor y,9y^2=x(x-3)^2 are y=(sqrt(x)(x-3))/3 ,y=-(sqrt(x)(x-3))/3
Find the zeros of solvefor y,9y^2=x(x-3)^2
The zeros of solvefor y,9y^2=x(x-3)^2 are y=(sqrt(x)(x-3))/3 ,y=-(sqrt(x)(x-3))/3