What are the solutions to the equation -2x^2-36x-282=0 ?

The solutions to the equation -2x^2-36x-282=0 are x=-9-2sqrt(15)i,x=-9+2sqrt(15)i

Find the zeros of -2x^2-36x-282=0

The zeros of -2x^2-36x-282=0 are x=-9-2sqrt(15)i,x=-9+2sqrt(15)i

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- 2 x^{2} - 36 x - 282 = 0

x = - 9 - 215 i, x = - 9 + 215 i

Solution steps

- 2 x^{2} - 36 x - 282 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 ( - 2 ) ( - 282 )}{2 ( - 2 )}

Simplify

(- 36)^{2} - 4 (- 2) (- 282) : 815 i

x_{1, 2} = \frac{- ( - 36 ) \pm 8 15 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 8 15 i}{2 ( - 2 )}, x_{2} = \frac{- ( - 36 ) - 8 15 i}{2 ( - 2 )}

x = \frac{- ( - 36 ) + 8 15 i}{2 ( - 2 )} : - 9 - 215 i

x = \frac{- ( - 36 ) - 8 15 i}{2 ( - 2 )} : - 9 + 215 i

The solutions to the quadratic equation are:

x = - 9 - 215 i, x = - 9 + 215 i

2 x (x + 5) = 0

h^{2} = 4 0^{2} - 3 0^{2}

3 x^{2} + 26 x + 35 = 0

n^{2} - n - 2 = 0

3 x^{2} + 4 x + 5

What are the solutions to the equation -2x^2-36x-282=0 ?
The solutions to the equation -2x^2-36x-282=0 are x=-9-2sqrt(15)i,x=-9+2sqrt(15)i
Find the zeros of -2x^2-36x-282=0
The zeros of -2x^2-36x-282=0 are x=-9-2sqrt(15)i,x=-9+2sqrt(15)i