What are the solutions to the equation -4x^2+2x+2=0 ?

The solutions to the equation -4x^2+2x+2=0 are x=-1/2 ,x=1

Find the zeros of -4x^2+2x+2=0

The zeros of -4x^2+2x+2=0 are x=-1/2 ,x=1

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- 4 x^{2} + 2 x + 2 = 0

x = - \frac{1}{2}, x = 1

Decimal Notation

x = - 0.5, x = 1

Solution steps

- 4 x^{2} + 2 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 4 ) \cdot 2}{2 ( - 4 )}

2^{2} - 4 (- 4) \cdot 2 = 6

x_{1, 2} = \frac{- 2 \pm 6}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 2 + 6}{2 ( - 4 )}, x_{2} = \frac{- 2 - 6}{2 ( - 4 )}

x = \frac{- 2 + 6}{2 ( - 4 )} : - \frac{1}{2}

x = \frac{- 2 - 6}{2 ( - 4 )} : 1

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = 1

x = 9 - x^{2}

k^{2} - 11 k + 30 = 0

3 n^{2} - 2 n - 2 = 0

c^{2} - 3 c = 0

(5 x - 2) (2 x + 3) = 0

What are the solutions to the equation -4x^2+2x+2=0 ?
The solutions to the equation -4x^2+2x+2=0 are x=-1/2 ,x=1
Find the zeros of -4x^2+2x+2=0
The zeros of -4x^2+2x+2=0 are x=-1/2 ,x=1