What are the solutions to the equation (z^2)/6-(3z)/2-6=0 ?

The solutions to the equation (z^2)/6-(3z)/2-6=0 are z=12,z=-3

Find the zeros of (z^2)/6-(3z)/2-6=0

The zeros of (z^2)/6-(3z)/2-6=0 are z=12,z=-3

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\frac{z ^{2}}{6} - \frac{3 z}{2} - 6 = 0

z = 12, z = - 3

Solution steps

\frac{z ^{2}}{6} - \frac{3 z}{2} - 6 = 0

Find Least Common Multiplier of

6, 2 : 6

Multiply by LCM=

6

\frac{z ^{2}}{6} \cdot 6 - \frac{3 z}{2} \cdot 6 - 6 \cdot 6 = 0 \cdot 6

Simplify

z^{2} - 9 z - 36 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot (- 36) = 15

z_{1, 2} = \frac{- ( - 9 ) \pm 15}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 9 ) + 15}{2 \cdot 1}, z_{2} = \frac{- ( - 9 ) - 15}{2 \cdot 1}

z = \frac{- ( - 9 ) + 15}{2 \cdot 1} : 12

z = \frac{- ( - 9 ) - 15}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

z = 12, z = - 3

6 y^{2} - 3 y = 0

3 x - 4 = 14

3 a^{2} - 14 a + 8

10 x^{2} + 3 = 3 x^{2} - 10 x

2 ab + 2 a - 3 b - 3

What are the solutions to the equation (z^2)/6-(3z)/2-6=0 ?
The solutions to the equation (z^2)/6-(3z)/2-6=0 are z=12,z=-3
Find the zeros of (z^2)/6-(3z)/2-6=0
The zeros of (z^2)/6-(3z)/2-6=0 are z=12,z=-3