What are the solutions to the equation 8x^2+157x-60=0 ?

The solutions to the equation 8x^2+157x-60=0 are x= 3/8 ,x=-20

Find the zeros of 8x^2+157x-60=0

The zeros of 8x^2+157x-60=0 are x= 3/8 ,x=-20

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8 x^{2} + 157 x - 60 = 0

x = \frac{3}{8}, x = - 20

Decimal Notation

x = 0.375, x = - 20

Solution steps

8 x^{2} + 157 x - 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 157 \pm 15 7 ^{2} - 4 \cdot 8 ( - 60 )}{2 \cdot 8}

15 7^{2} - 4 \cdot 8 (- 60) = 163

x_{1, 2} = \frac{- 157 \pm 163}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 157 + 163}{2 \cdot 8}, x_{2} = \frac{- 157 - 163}{2 \cdot 8}

x = \frac{- 157 + 163}{2 \cdot 8} : \frac{3}{8}

x = \frac{- 157 - 163}{2 \cdot 8} : - 20

The solutions to the quadratic equation are:

x = \frac{3}{8}, x = - 20

3 x - 2 = x^{2}

2 x^{2} + 3 = 9

x^{2} + 8 x - 33 = 9

x^{2} + 18 x - 40 = 0

x (x + 4) = - 29

What are the solutions to the equation 8x^2+157x-60=0 ?
The solutions to the equation 8x^2+157x-60=0 are x= 3/8 ,x=-20
Find the zeros of 8x^2+157x-60=0
The zeros of 8x^2+157x-60=0 are x= 3/8 ,x=-20