What are the solutions to the equation (x-6)(x+1)=0 ?

The solutions to the equation (x-6)(x+1)=0 are x=6,x=-1

Find the zeros of (x-6)(x+1)=0

The zeros of (x-6)(x+1)=0 are x=6,x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x - 6) (x + 1) = 0

x = 6, x = - 1

Solution steps

(x - 6) (x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 6 = 0 or x + 1 = 0

Solve

x - 6 = 0 : x = 6

Solve

x + 1 = 0 : x = - 1

The solutions to the quadratic equation are:

x = 6, x = - 1

y, (x + y)^{2} + (x - y)^{2} = x^{3} + y^{2}

x^{2} + 5 x + 15 = 0

7 n^{2} + 9 n + 2 = 0

(x + 2)^{2} - 5 = 19

x, - x^{2} + 2 x y - 1 = 0

What are the solutions to the equation (x-6)(x+1)=0 ?
The solutions to the equation (x-6)(x+1)=0 are x=6,x=-1
Find the zeros of (x-6)(x+1)=0
The zeros of (x-6)(x+1)=0 are x=6,x=-1