What are the solutions to the equation 81x^2-18x+1=0 ?

The solutions to the equation 81x^2-18x+1=0 are x= 1/9

Find the zeros of 81x^2-18x+1=0

The zeros of 81x^2-18x+1=0 are x= 1/9

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81 x^{2} - 18 x + 1 = 0

x = \frac{1}{9}

Decimal Notation

x = 0.11111 \dots

Solution steps

81 x^{2} - 18 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 81 \cdot 1}{2 \cdot 81}

(- 18)^{2} - 4 \cdot 81 \cdot 1 = 0

x_{1, 2} = \frac{- ( - 18 ) \pm 0}{2 \cdot 81}

x = \frac{- ( - 18 )}{2 \cdot 81}

\frac{- ( - 18 )}{2 \cdot 81} = \frac{1}{9}

x = \frac{1}{9}

The solution to the quadratic equation is:

x = \frac{1}{9}

6 (x^{2} - 1) = 3 (x^{2} + x) - 1

x^{2} = - 90

x^{2} + (x + 2)^{2} = 212

- 3 x^{2} = 12 x + 12

5 x^{2} + 4 x - 7 = 0

What are the solutions to the equation 81x^2-18x+1=0 ?
The solutions to the equation 81x^2-18x+1=0 are x= 1/9
Find the zeros of 81x^2-18x+1=0
The zeros of 81x^2-18x+1=0 are x= 1/9