What are the solutions to the equation 4p^2+23=7 ?

The solutions to the equation 4p^2+23=7 are p=2i,p=-2i

Find the zeros of 4p^2+23=7

The zeros of 4p^2+23=7 are p=2i,p=-2i

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4 p^{2} + 23 = 7

p = 2 i, p = - 2 i

Solution steps

4 p^{2} + 23 = 7

Move

23

to the right side

4 p^{2} = - 16

Divide both sides by

4

p^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

p = - 4, p = - - 4

- 4 = 2 i

- - 4 = - 2 i

p = 2 i, p = - 2 i

x^{2} = 0.1

b, N b^{2} - r = 3 T

x^{2} = 17 x

6 x^{2} + 6 x + 36 = 0

x^{2} = 130

What are the solutions to the equation 4p^2+23=7 ?
The solutions to the equation 4p^2+23=7 are p=2i,p=-2i
Find the zeros of 4p^2+23=7
The zeros of 4p^2+23=7 are p=2i,p=-2i