What are the solutions to the equation -8x^2+2x+6=0 ?

The solutions to the equation -8x^2+2x+6=0 are x=-3/4 ,x=1

Find the zeros of -8x^2+2x+6=0

The zeros of -8x^2+2x+6=0 are x=-3/4 ,x=1

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- 8 x^{2} + 2 x + 6 = 0

x = - \frac{3}{4}, x = 1

Decimal Notation

x = - 0.75, x = 1

Solution steps

- 8 x^{2} + 2 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 8 ) \cdot 6}{2 ( - 8 )}

2^{2} - 4 (- 8) \cdot 6 = 14

x_{1, 2} = \frac{- 2 \pm 14}{2 ( - 8 )}

Separate the solutions

x_{1} = \frac{- 2 + 14}{2 ( - 8 )}, x_{2} = \frac{- 2 - 14}{2 ( - 8 )}

x = \frac{- 2 + 14}{2 ( - 8 )} : - \frac{3}{4}

x = \frac{- 2 - 14}{2 ( - 8 )} : 1

The solutions to the quadratic equation are:

x = - \frac{3}{4}, x = 1

\frac{64 - m ^{3}}{( 4 - m ) ^{3}}

\frac{3 z}{4} + 5 \leq - 1

a^{2} + 36 b^{2} - 12 ab

x - 10 = 5

(- \frac{1}{4})^{5}

What are the solutions to the equation -8x^2+2x+6=0 ?
The solutions to the equation -8x^2+2x+6=0 are x=-3/4 ,x=1
Find the zeros of -8x^2+2x+6=0
The zeros of -8x^2+2x+6=0 are x=-3/4 ,x=1