What are the solutions to the equation 5x^2+10x-8=0 ?

The solutions to the equation 5x^2+10x-8=0 are x=(-5+sqrt(65))/5 ,x=-(5+sqrt(65))/5

Find the zeros of 5x^2+10x-8=0

The zeros of 5x^2+10x-8=0 are x=(-5+sqrt(65))/5 ,x=-(5+sqrt(65))/5

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5 x^{2} + 10 x - 8 = 0

x = \frac{- 5 + 65}{5}, x = - \frac{5 + 65}{5}

Decimal Notation

x = 0.61245 \dots, x = - 2.61245 \dots

Solution steps

5 x^{2} + 10 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 5 ( - 8 )}{2 \cdot 5}

1 0^{2} - 4 \cdot 5 (- 8) = 265

x_{1, 2} = \frac{- 10 \pm 2 65}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 10 + 2 65}{2 \cdot 5}, x_{2} = \frac{- 10 - 2 65}{2 \cdot 5}

x = \frac{- 10 + 2 65}{2 \cdot 5} : \frac{- 5 + 65}{5}

x = \frac{- 10 - 2 65}{2 \cdot 5} : - \frac{5 + 65}{5}

The solutions to the quadratic equation are:

x = \frac{- 5 + 65}{5}, x = - \frac{5 + 65}{5}

4 k (k + 13) = 13

7 x^{2} + x = 0

x^{2} + 22 x + 40 = 0

2 x^{2} + 12 x - 6 = 0

x^{2} = 12 \cdot 3

What are the solutions to the equation 5x^2+10x-8=0 ?
The solutions to the equation 5x^2+10x-8=0 are x=(-5+sqrt(65))/5 ,x=-(5+sqrt(65))/5
Find the zeros of 5x^2+10x-8=0
The zeros of 5x^2+10x-8=0 are x=(-5+sqrt(65))/5 ,x=-(5+sqrt(65))/5