What are the solutions to the equation 11c^2+27c+14=2c^2 ?

The solutions to the equation 11c^2+27c+14=2c^2 are c=-2/3 ,c=-7/3

Find the zeros of 11c^2+27c+14=2c^2

The zeros of 11c^2+27c+14=2c^2 are c=-2/3 ,c=-7/3

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11 c^{2} + 27 c + 14 = 2 c^{2}

c = - \frac{2}{3}, c = - \frac{7}{3}

Decimal Notation

c = - 0.66666 \dots, c = - 2.33333 \dots

Solution steps

11 c^{2} + 27 c + 14 = 2 c^{2}

Move

2 c^{2}

to the left side

9 c^{2} + 27 c + 14 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 27 \pm 2 7 ^{2} - 4 \cdot 9 \cdot 14}{2 \cdot 9}

2 7^{2} - 4 \cdot 9 \cdot 14 = 15

c_{1, 2} = \frac{- 27 \pm 15}{2 \cdot 9}

Separate the solutions

c_{1} = \frac{- 27 + 15}{2 \cdot 9}, c_{2} = \frac{- 27 - 15}{2 \cdot 9}

c = \frac{- 27 + 15}{2 \cdot 9} : - \frac{2}{3}

c = \frac{- 27 - 15}{2 \cdot 9} : - \frac{7}{3}

The solutions to the quadratic equation are:

c = - \frac{2}{3}, c = - \frac{7}{3}

5 x^{2} + 10 x - 2 = 0

x, 36 x^{2} - 36 x + 36 y^{2} + 24 y + 13 = 0

2 - 3 x - 2 x^{2} = 0

m^{2} + 100 m + 2500 = 0

2 r^{2} - 3 r - 4 = 0

What are the solutions to the equation 11c^2+27c+14=2c^2 ?
The solutions to the equation 11c^2+27c+14=2c^2 are c=-2/3 ,c=-7/3
Find the zeros of 11c^2+27c+14=2c^2
The zeros of 11c^2+27c+14=2c^2 are c=-2/3 ,c=-7/3