What are the solutions to the equation quadraticformula x^2-2x+3=0 ?

The solutions to the equation quadraticformula x^2-2x+3=0 are x=1+sqrt(2)i,x=1-sqrt(2)i

Find the zeros of quadraticformula x^2-2x+3=0

The zeros of quadraticformula x^2-2x+3=0 are x=1+sqrt(2)i,x=1-sqrt(2)i

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x^{2} - 2 x + 3 = 0

x = 1 + 2 i, x = 1 - 2 i

Solution steps

x^{2} - 2 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 3 : 22 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 2 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 2 i}{2 \cdot 1} : 1 + 2 i

x = \frac{- ( - 2 ) - 2 2 i}{2 \cdot 1} : 1 - 2 i

The solutions to the quadratic equation are:

x = 1 + 2 i, x = 1 - 2 i

2 + 8 + 14 + (6 n - 4) = n (3 n - 1)

x^{2} - 11 x + 18

u, (2 uv)^{2} = 4 - 4 (u^{2} - v^{2})

(h + 10) (h) = 600

8 g^{2} + 8 g + 2 = 0

What are the solutions to the equation quadraticformula x^2-2x+3=0 ?
The solutions to the equation quadraticformula x^2-2x+3=0 are x=1+sqrt(2)i,x=1-sqrt(2)i
Find the zeros of quadraticformula x^2-2x+3=0
The zeros of quadraticformula x^2-2x+3=0 are x=1+sqrt(2)i,x=1-sqrt(2)i